n(n^2-3n+2)(n^2-7n+12)=120

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Solution for n(n^2-3n+2)(n^2-7n+12)=120 equation: 



n(n^2-3n+2)(n^2-7n+12)=120

We move all terms to the left:

n(n^2-3n+2)(n^2-7n+12)-(120)=0

We move all terms containing n to the left, all other terms to the right

n(n^2-3n+2)(n^2-7n+12)=120

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